Bash - pushd

With no arguments

pushd 

With no arguments, exchanges the top two directories and returns 0, unless the directory stack is empty.

First Form

pushd [-n] [dir]

if supplied, have the following meanings:

• -n: Rotates the stack so that the nth directory (counting from the right of the list shown by dirs, starting with zero) is at the top.
• or ?? -n Suppresses the normal change of directory when adding directories to the stack, so that only the stack is manipulated.
• dir Adds dir to the directory stack at the top, making it the new current working directory.

pushd returns 0 unless the cd to dir fails.

Second Form

pushd [-n] [+n] [-n]

where:

• +n: Rotates the stack so that the nth directory (counting from the left of the list shown by dirs, starting with zero) is at the top.
• -n: Rotates the stack so that the nth directory (counting from the right of the list shown by dirs, starting with zero) is at the top.
• -n Suppresses the normal change of directory when adding directories to the stack, so that only the stack is manipulated.

pushd returns 0 unless the directory stack is empty, a non-existent directory stack element is specified, or the directory change to the specified new current directory fails.

Go away and returns

# we are now in /
pushd /aDir/
# we are now in /aDir/
popd
# we are now back in the starting current directory /